TSTP Solution File: NUM688^1 by Duper---1.0
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% File : Duper---1.0
% Problem : NUM688^1 : TPTP v8.1.2. Released v3.7.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n028.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 10:57:03 EDT 2023
% Result : Theorem 3.62s 3.79s
% Output : Proof 3.62s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.12 % Problem : NUM688^1 : TPTP v8.1.2. Released v3.7.0.
% 0.12/0.13 % Command : duper %s
% 0.12/0.34 % Computer : n028.cluster.edu
% 0.12/0.34 % Model : x86_64 x86_64
% 0.12/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34 % Memory : 8042.1875MB
% 0.12/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34 % CPULimit : 300
% 0.12/0.34 % WCLimit : 300
% 0.12/0.34 % DateTime : Fri Aug 25 09:20:20 EDT 2023
% 0.12/0.34 % CPUTime :
% 3.62/3.79 SZS status Theorem for theBenchmark.p
% 3.62/3.79 SZS output start Proof for theBenchmark.p
% 3.62/3.79 Clause #0 (by assumption #[]): Eq (more x y) True
% 3.62/3.79 Clause #1 (by assumption #[]): Eq (Not (more z u) → Eq z u) True
% 3.62/3.79 Clause #3 (by assumption #[]): Eq (∀ (Xx Xy Xz Xu : nat), Eq Xx Xy → more Xz Xu → more (pl Xz Xx) (pl Xu Xy)) True
% 3.62/3.79 Clause #4 (by assumption #[]): Eq (∀ (Xx Xy Xz Xu : nat), more Xx Xy → more Xz Xu → more (pl Xx Xz) (pl Xy Xu)) True
% 3.62/3.79 Clause #5 (by assumption #[]): Eq (Not (more (pl x z) (pl y u))) True
% 3.62/3.79 Clause #10 (by clausification #[1]): Or (Eq (Not (more z u)) False) (Eq (Eq z u) True)
% 3.62/3.79 Clause #11 (by clausification #[10]): Or (Eq (Eq z u) True) (Eq (more z u) True)
% 3.62/3.79 Clause #12 (by clausification #[11]): Or (Eq (more z u) True) (Eq z u)
% 3.62/3.79 Clause #13 (by clausification #[5]): Eq (more (pl x z) (pl y u)) False
% 3.62/3.79 Clause #14 (by clausification #[4]): ∀ (a : nat), Eq (∀ (Xy Xz Xu : nat), more a Xy → more Xz Xu → more (pl a Xz) (pl Xy Xu)) True
% 3.62/3.79 Clause #15 (by clausification #[14]): ∀ (a a_1 : nat), Eq (∀ (Xz Xu : nat), more a a_1 → more Xz Xu → more (pl a Xz) (pl a_1 Xu)) True
% 3.62/3.79 Clause #16 (by clausification #[15]): ∀ (a a_1 a_2 : nat), Eq (∀ (Xu : nat), more a a_1 → more a_2 Xu → more (pl a a_2) (pl a_1 Xu)) True
% 3.62/3.79 Clause #17 (by clausification #[16]): ∀ (a a_1 a_2 a_3 : nat), Eq (more a a_1 → more a_2 a_3 → more (pl a a_2) (pl a_1 a_3)) True
% 3.62/3.79 Clause #18 (by clausification #[17]): ∀ (a a_1 a_2 a_3 : nat), Or (Eq (more a a_1) False) (Eq (more a_2 a_3 → more (pl a a_2) (pl a_1 a_3)) True)
% 3.62/3.79 Clause #19 (by clausification #[18]): ∀ (a a_1 a_2 a_3 : nat),
% 3.62/3.79 Or (Eq (more a a_1) False) (Or (Eq (more a_2 a_3) False) (Eq (more (pl a a_2) (pl a_1 a_3)) True))
% 3.62/3.79 Clause #20 (by superposition #[19, 0]): ∀ (a a_1 : nat), Or (Eq (more a a_1) False) (Or (Eq (more (pl x a) (pl y a_1)) True) (Eq False True))
% 3.62/3.79 Clause #22 (by clausification #[3]): ∀ (a : nat), Eq (∀ (Xy Xz Xu : nat), Eq a Xy → more Xz Xu → more (pl Xz a) (pl Xu Xy)) True
% 3.62/3.79 Clause #23 (by clausification #[22]): ∀ (a a_1 : nat), Eq (∀ (Xz Xu : nat), Eq a a_1 → more Xz Xu → more (pl Xz a) (pl Xu a_1)) True
% 3.62/3.79 Clause #24 (by clausification #[23]): ∀ (a a_1 a_2 : nat), Eq (∀ (Xu : nat), Eq a a_1 → more a_2 Xu → more (pl a_2 a) (pl Xu a_1)) True
% 3.62/3.79 Clause #25 (by clausification #[24]): ∀ (a a_1 a_2 a_3 : nat), Eq (Eq a a_1 → more a_2 a_3 → more (pl a_2 a) (pl a_3 a_1)) True
% 3.62/3.79 Clause #26 (by clausification #[25]): ∀ (a a_1 a_2 a_3 : nat), Or (Eq (Eq a a_1) False) (Eq (more a_2 a_3 → more (pl a_2 a) (pl a_3 a_1)) True)
% 3.62/3.79 Clause #27 (by clausification #[26]): ∀ (a a_1 a_2 a_3 : nat), Or (Eq (more a a_1 → more (pl a a_2) (pl a_1 a_3)) True) (Ne a_2 a_3)
% 3.62/3.79 Clause #28 (by clausification #[27]): ∀ (a a_1 a_2 a_3 : nat), Or (Ne a a_1) (Or (Eq (more a_2 a_3) False) (Eq (more (pl a_2 a) (pl a_3 a_1)) True))
% 3.62/3.79 Clause #29 (by destructive equality resolution #[28]): ∀ (a a_1 a_2 : nat), Or (Eq (more a a_1) False) (Eq (more (pl a a_2) (pl a_1 a_2)) True)
% 3.62/3.79 Clause #30 (by superposition #[29, 0]): ∀ (a : nat), Or (Eq (more (pl x a) (pl y a)) True) (Eq False True)
% 3.62/3.79 Clause #32 (by clausification #[30]): ∀ (a : nat), Eq (more (pl x a) (pl y a)) True
% 3.62/3.79 Clause #38 (by clausification #[20]): ∀ (a a_1 : nat), Or (Eq (more a a_1) False) (Eq (more (pl x a) (pl y a_1)) True)
% 3.62/3.79 Clause #40 (by superposition #[38, 12]): Or (Eq (more (pl x z) (pl y u)) True) (Or (Eq False True) (Eq z u))
% 3.62/3.79 Clause #47 (by clausification #[40]): Or (Eq (more (pl x z) (pl y u)) True) (Eq z u)
% 3.62/3.79 Clause #48 (by superposition #[47, 13]): Or (Eq z u) (Eq True False)
% 3.62/3.79 Clause #59 (by clausification #[48]): Eq z u
% 3.62/3.79 Clause #61 (by backward demodulation #[59, 13]): Eq (more (pl x u) (pl y u)) False
% 3.62/3.79 Clause #66 (by superposition #[61, 32]): Eq False True
% 3.62/3.79 Clause #67 (by clausification #[66]): False
% 3.62/3.79 SZS output end Proof for theBenchmark.p
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